Table 2 Results of PAML analyses testing for selection on the three mitochondrial subunits

ND4

M0 (one-ratio)

1

ω0 = 0.0372

− 7708.624

–

M0 vs M1a

M0 vs M3

M1a vs M2a

M7 vs M8

 < 0.001

 < 0.001

 < 0.001

 < 0.001

M1 (neutral)

2

ω0 = 0.0074 p0 = 0.9469 ω1 = 1.000 p1 = 0.0531

− 7645.299

–

M2 (selection)

4

ω0 = 0.0072 p0 = 0.947 ω1 = 1.0000 p1 = 0.0523 ω2 = 2.1673 p2 = 0.0002

− 7504.371

29

M3 (discrete)

5

ω0 = 0.0063 p0 = 0.9425 ω1 = 0.6554 p1 = 0.0575 ω2 = 217.8820 p2 = 0.0000

− 7497.046

–

M7 (beta)

2

p = 0.0062 q = 0.005

− 8315.174

–

M8 (beta&ω)

4

p0 = 0.9658 p = 0.0631 q = 2.7963 (p1 = 0.0342) ω = 1.0000

− 7499.443

29

CytB

M0 (one-ratio)

1

ω0 = 0.0320

− 5881.359

–

M0 vs M1a

M0 vs M3

M1a vs M2a

M7 vs M8

 < 0.001

 < 0.001

 > 0.05

 > 0.05

M1 (neutral)

2

ω0 = 0.0115 p0 = 0.9660 ω1 = 1.000 p1 = 0.0340

− 5774.833

–

M2 (selection)

4

ω0 = 0.0115 p0 = 0.9660 ω1 = 1.000 p1 = 0.0340 ω2 = 14.7728 p2 = 0.0000

− 5785.211

–

M3 (discrete)

5

ω0 = 0.0072 p0 = 0.9469 ω1 = 0.4605 p1 = 0.0531 ω2 = 14.1110 p2 = 0.0000

− 5785.565

–

M7 (beta)

2

p = 0.0165 q = 0.0239

− 5908.619

–

M8 (beta&ω)

4

p0 = 0.9999 p = 0.0590 q = 1.0510 (p1 = 0.00001) ω = 6.0347

− 5911.451

–

cox1

M0 (one-ratio)

1

ω0 = 0.0047

− 5912.722

–

M0 vs M1a

M0 vs M3

M1a vs M2a

M7 vs M8

 > 0.05

 > 0.05

 > 0.05

 < 0.001

M1 (neutral)

2

ω0 = 0.0039 p0 = 0.9974 ω1 = 1.000 p1 = 0.0027

− 5910.938

–

M2 (selection)

4

ω0 = 0.0039 p0 = 0.9974 ω1 = 1.000 p1 = 0.0026 ω2 = 34.4363 p2 = 0.0000

− 5911.120

–

M3 (discrete)

5

ω0 = 0.0038 p0 = 0.9966 ω1 = 0.5872 p1 = 0.0034 ω2 = 6.8990 p2 = 0.0000

− 5911.043

–

M7 (beta)

2

p = 0.0101 q = 0.0086

− 6208.708

–

M8 (beta&ω)

4

p0 = 0.9999 p = 0.0564 q = 6.7184 (p1 = 0.00001) ω = 6.2162

− 5911.451

–